2x^2-(3x-4)=3x-5

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Solution for 2x^2-(3x-4)=3x-5 equation: 



2x^2-(3x-4)=3x-5

We move all terms to the left:

2x^2-(3x-4)-(3x-5)=0

We get rid of parentheses

2x^2-3x-3x+4+5=0

We add all the numbers together, and all the variables

2x^2-6x+9=0

a = 2; b = -6; c = +9;
Δ = b2-4ac
Δ = -62-4·2·9
Δ = -36
Delta is less than zero, so there is no solution for the equation

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